View Full Version : Homework helper/solver

PixieMan

05-31-2016, 12:09 PM

Many of the forumers here are students currently so I would like to introduce a homework helper thing.

Basically if you need help for your homework, cannot understand a certain concept, need advises feel free to post them.

If you can answer the questions that others have difficulty with kindly lend them a helping hand.

You can either ask for help/help others.

English

Math (A math/e math/math olympiad)

Science(different type of sciences)

Anyway only ask questions that are related to these if yours is mother tongue which is in foreign language for others you might not help the help you wanted.

genpasaporte922

05-31-2016, 12:22 PM

I need help on Science (astronomy).

“What will be the fate of our universe?”

Notavailable

05-31-2016, 12:27 PM

Help my brother :

1. (3x-2)(x^3+3^3+18x+6x²)=0. Find x.

2. Age sum of me and my bro is 30. He is 2 years old smaller than me. Age of me and of him ? (Real age irl, lol)

More to come, if u wish, lel.

Sebastian Elson Gunawan

05-31-2016, 12:32 PM

Help my brother :

1. (3x-2)(x^3+3^3+18x+6x²)=0. Find x.

2. Age sum of me and my bro is 30. He is 2 years old smaller than me. Age of me and of him ? (Real age irl, lol)

More to come, if u wish, lel.

I am to lazy to do math

But number 2 your age is 16 your brother 14 (I am using logic)

Notavailable

05-31-2016, 01:15 PM

I am to lazy to do math

But number 2 your age is 16 your brother 14 (I am using logic)

Yea, summer is coming and no one wants to do it.

(the 2nd one doesn't need brain to do, though)

VendLolx

05-31-2016, 01:20 PM

I need help. How much is 1+1?

Notavailable

05-31-2016, 01:31 PM

I need help. How much is 1+1?

1+1=21. Really dude ? Learn some common sense.

Meercats

05-31-2016, 01:43 PM

1+1=21. Really dude ? Learn some common sense.

Srsly.. 21..

dronshi

05-31-2016, 01:54 PM

Help my brother :

1. (3x-2)(x^3+3^3+18x+6x²)=0. Find x.

More to come, if u wish, lel.

Teach him this and he'll get better in math, unless he really learns slow.:sweatdrop:

1. Just by looking at the question (3x-2)(x3+33+18x+6x2)=0. Find x.

You'd know that the value of the x is x<0, in other words, a negative integer.

How did I know that? Seeing that the final operation that will be used is multiplication and seeing that the product must be 0, you can tell that one or both of the polynomials must be 0.

Also since all operations used on the second polynomial are addition, meaning that if I use a positive integer for the value of x, I will never ever get a sum of 0 on the second polynomial.

Its obvious that the first polynomial can't be zero whatever integer you use to represent x, so we will try to solve the second polynomial first.

I will use trial and error since this is the method I always use and I might have forgot other methods for this kind of problem, if there are other methods that is.

Now let's look at the second polynomial (x3+33+18x+6x2).

If you know how negative integers work with exponents, you know that having a odd number for an exponent means that the answer will also be negative and having a even number for an exponent means that the answer will always be positive.

So basically the answer will be like this [(-a)+(-b)+(-c)+d], the first and third monomials (x3,18x respectively) would negative integers and the second and last monomial (33,6x2 respectively) would be definitely a positive integer if simplified.

Now we should try using -1 for our value for x first, since -1 is the easiest to solve and getting the value would give you an idea on what the answer really is.

Substitute -1 to all x.

[3(-1)-2][(-1)3+33+18(-1)+6(-1)2]=0

Then simplify.

[3(-1)-2][(-1)3+33+18(-1)+6(-1)2]=0

[-3(-2)][(-1)+27+(-18)+12]=0

-5(14) =0

-70=0

Meaning x≠-1

I will try -3 next as the value for x.

Again, substitute -3 for all values.

[3(-3)-2][(-3)3+33+18(-3)+6(-3)2]=0

Then simplify.

[3(-3)-2][(-3)3+33+18(-3)+6(-3)2]=0

[-9(-2)][(-27)+27+(-54)+54]=0

-11(0)=0

0=0

Therefore x=-3

Singapore

05-31-2016, 02:07 PM

Help my brother :

1. (3x-2)(x^3+3^3+18x+6x²)=0. Find x.

2. Age sum of me and my bro is 30. He is 2 years old smaller than me. Age of me and of him ? (Real age irl, lol)

More to come, if u wish, lel.

1. (3x-2)(x^3+3^3+18x+6x²)=0. Find x.

I know for sure one of the solutions is x=2/3 but I'm too tired to find the other one.

- - - Updated - - -

Teach him this and he'll get better in math, unless he really learns slow.:sweatdrop:

1. Just by looking at the question (3x-2)(x3+33+18x+6x2)=0. Find x.

You'd know that the value of the x is x<0, in other words, a negative integer.

How did I know that? Seeing that the final operation that will be used is multiplication and seeing that the product must be 0, you can tell that one or both of the polynomials must be 0.

Also since all operations used on the second polynomial are addition, meaning that if I use a positive integer for the value of x, I will never ever get a sum of 0 on the second polynomial.

Its obvious that the first polynomial can't be zero whatever integer you use to represent x, so we will try to solve the second polynomial first.

I will use trial and error since this is the method I always use and I might have forgot other methods for this kind of problem, if there are other methods that is.

Now let's look at the second polynomial (x3+33+18x+6x2).

If you know how negative integers work with exponents, you know that having a odd number for an exponent means that the answer will also be negative and having a even number for an exponent means that the answer will always be positive.

So basically the answer will be like this [(-a)+(-b)+(-c)+d], the first and third monomials (x3,18x respectively) would negative integers and the second and last monomial (33,6x2 respectively) would be definitely a positive integer if simplified.

Now we should try using -1 for our value for x first, since -1 is the easiest to solve and getting the value would give you an idea on what the answer really is.

Substitute -1 to all x.

[3(-1)-2][(-1)3+33+18(-1)+6(-1)2]=0

Then simplify.

[3(-1)-2][(-1)3+33+18(-1)+6(-1)2]=0

[-3(-2)][(-1)+27+(-18)+12]=0

-5(14) =0

-70=0

Meaning x≠-1

I will try -3 next as the value for x.

Again, substitute -3 for all values.

[3(-3)-2][(-3)3+33+18(-3)+6(-3)2]=0

Then simplify.

[3(-3)-2][(-3)3+33+18(-3)+6(-3)2]=0

[-9(-2)][(-27)+27+(-54)+54]=0

-11(0)=0

0=0

Therefore x=-3

This is correct.

Answer: x=-3 or x=2/3

Write down both, they are correct answers.

PixieMan

05-31-2016, 02:08 PM

Singapore math olympiad question

Anyone up for it?

126055

KKcupcake

05-31-2016, 02:25 PM

Singapore math olympiad question

Anyone up for it?

126055

hahaha i just did the paper

...

i completed 4 qns. lmao.

PixieMan

05-31-2016, 02:29 PM

hahaha i just did the paper

...

i completed 4 qns. lmao.

help.......

Btw can estimate the cut off point for bronze and honorable mention?

Singapore

05-31-2016, 02:37 PM

hahaha i just did the paper

...

i completed 4 qns. lmao.

You need special training to do maths olympiad questions lol, but it's almost useless unless you pay for outside classes for Maths Olympiad training.

I wonder if OP is my tuition teacher lmao.

PixieMan

05-31-2016, 11:58 PM

You need special training to do maths olympiad questions lol, but it's almost useless unless you pay for outside classes for Maths Olympiad training.

I wonder if OP is my tuition teacher lmao.

Nah I am not that smart just a student taking smo junior lol

Masqueraded

06-01-2016, 12:09 AM

Please explain light-dependent reactions in photosynthesis in full detail. I am actually not grasping this concept, and research further perplexes me.

Notavailable

06-01-2016, 01:01 AM

"Buffalo buffalo Buffalo buffalo buffalo buffalo Buffalo buffalo"

Tell me, how this makes sense. (no google pls, u can do it)

"That that is is that that is not is not is that it it is"

And, add punctuation to this sentence, please.

KKcupcake

06-01-2016, 01:08 AM

You need special training to do maths olympiad questions lol, but it's almost useless unless you pay for outside classes for Maths Olympiad training.

I wonder if OP is my tuition teacher lmao.

i did, my school provided it, but i didn't understand 99% of what the trainer said.

((makes me wonder how i even got selected))

JOSHIE63

06-01-2016, 01:09 AM

"Buffalo buffalo Buffalo buffalo buffalo buffalo Buffalo buffalo"

Tell me, how this makes sense. (no google pls, u can do it)

"That that is is that that is not is not is that it it is"

And, add punctuation to this sentence, please.

Panda panda panda...

To make this post relavant, the bottom is more than one sentence; otherwise, it is cluttered and messy.

ALEXOVER

06-01-2016, 01:11 AM

How do I summer? :rolleyes:

~Rock

Notavailable

06-01-2016, 01:13 AM

Panda panda panda...

To make this post relavant, the bottom is more than one sentence; otherwise, it is cluttered and messy.

Yes. Add as many full-stops as you want.

Singapore

06-01-2016, 04:03 AM

i did, my school provided it, but i didn't understand 99% of what the trainer said.

((makes me wonder how i even got selected))

My trainer regularly tells stories of higher-level students in A Maths getting 90% who can't do a single question in the training paper.

Welp, at least I got the participation certificate lol. Many classmates just skipped the training and didn't go for the test.

PixieMan

06-01-2016, 04:08 AM

Please explain light-dependent reactions in photosynthesis in full detail. I am actually not grasping this concept, and research further perplexes me.

In photosynthesis, the light-dependent reactions take place on the thylakoid membranes. The inside of the thylakoid membrane is called the lumen, and outside the thylakoid membrane is the stroma, where the light-independent reactions take place.

A diagram for you to look at:

https://upload.wikimedia.org/wikipedia/commons/4/49/Thylakoid_membrane_3.svg

Powered by vBulletin® Version 4.2.5 Copyright © 2019 vBulletin Solutions Inc. All rights reserved.